This thread is trying to answer question "Does the `locator.isVisible()` function wait for the element to become visible or does it return immediately?"
Related Ask AI answer for "What is the behavior of the `locator.isVisible()` function in Playwright?".
locator.isVisible() in PlaywrightIn Playwright, locator.isVisible() checks if an element is visible right away. It doesn't wait for the element to become visible.
Here's how it works:
import { test } from '@playwright/test';
test('Check visibility', async ({ page }) => {
await page.goto('https://ray.run');
const locator = page.locator('.your-selector');
const isVisible = await locator.isVisible();
console.log(isVisible);
});
If the selector doesn't match any elements, Playwright considers it not visible. So, if there are no matching elements in the DOM, locator.isVisible() will return false.
This might be different from what you're used to with other frameworks. Some wait for an element to become visible before returning a result. But with Playwright, you need to handle waiting explicitly if needed.
If you want to wait for an element to become visible, you can use waitFor(). This method lets you specify conditions based on various states of an element.
import { test } from '@playwright/test';
test('Wait for visibility', async ({ page }) => {
await page.goto('https://ray.run');
const locator = page.locator('.your-selector');
await locator.waitFor('visible');
// Perform further actions or assertions
});
So, remember, locator.isVisible() in Playwright returns immediately. If you need to wait for visibility changes, use waitFor().
Rayrun is a community for QA engineers. I am constantly looking for new ways to add value to people learning Playwright and other browser automation frameworks. If you have feedback, email luc@ray.run.