Hi all, in one of my tests I am verifying the values contained within a <select> drop-down, and I need to take a screenshot as evidence to show in the report. However when I take a screenshot after clicking on the <select>, the screenshot is showing the <select> as closed, so the options contained within are not visible. Any help on how to solve this would be appreciated! Thanks!
This thread is trying to answer question "How can I capture a screenshot of a <select> drop-down with the options visible?"
First, locate the
<select> element on your page with Playwright's
page.locator() method. This returns a Locator object for the element.
const selectLocator = await page.locator('select');
Next, interact with the
<select> element to make all options visible. Use the
element.selectOption() method to select options in
await selectLocator.selectOption(['red', 'green', 'blue']);
Now, you're ready to capture a screenshot of the element using
locator.screenshot(). This method captures a screenshot of the element and returns it as a Buffer.
const buffer = await selectLocator.screenshot();
This Buffer contains the image data for your screenshot. You can convert this buffer into other formats or save it to disk if needed.
Remember, if any part of your selected dropdown is covered by other elements or is not currently scrolled into view, those parts will not be captured in the screenshot. Also, if the dropdown gets detached from the DOM during these operations, these methods will throw an error. Handle these cases and errors according to your application's requirements.
Rayrun is a community for QA engineers. I am constantly looking for new ways to add value to people learning Playwright and other browser automation frameworks. If you have feedback, email email@example.com.