On Python, getting the message: "playwright._impl._api_types.Error: Connection closed"

Use Debug Mode to find where the issue is coming from https://docs.python.org/3.7/library/asyncio-dev.html#debug-mode

This is the error I get if I enable debug

Right now, my code looks like this:

import asyncio
import aiohttp
from bs4 import BeautifulSoup as bs
from playwright.async_api import async_playwright
from playwright._impl._api_types import TimeoutError as TOErr
from asyncio.exceptions import InvalidStateError

class TokenFactory:
    def __init__(self, url):
        self._url = url
        self._token = None
        self._retry_count = 0

    def change_url(self, url):
        self._url = url

    async def get_token(self):
        if self._token is None:
            await self.regenerate_token()    
        return self._token
    
    async def regenerate_token(self):
        try:
            async with async_playwright() as p:
                browser = await p.chromium.launch(headless=False)
                context = await browser.new_context()
                await context.add_init_script(
                    "Object.defineProperty(navigator, 'webdriver', {get: () => undefined})")
                page = await context.new_page()

                async with page.expect_response(lambda res: "testpattern" in res.url and res.status == 200) as response_info:
                    await page.goto(self._url)
                response_value = await response_info.value
                self._token = response_value.request.headers.get("x-access-token")
                self._retry_count = 0
        except (KeyError, TOErr, InvalidStateError):
             self._retry_count += 1
             if self._retry_count > 5:
                 raise Exception("Too many retries to regenerate token. Exiting...")
             self.regenerate_token()

async def test():
    factory = TokenFactory("google.com")
    token = await factory.get_token()
    print(token)

asyncio.run(test(), debug=True)

The thing is, it's printing the correct token, but it also shows the error without halting execution